Learning Center Schedule:
Handouts:
Assignments:
Section |
Assigned Problems |
Due Date |
2 |
#1, 2, 3, 4, 5, 6, 9a; extra credit: #9b | 9-14 |
3
|
#1, 2, 3, 4, 5, 6, 7 | 9-14 |
4 |
#1, 4, 6, 8, 11, 13 | 9-14 |
5 |
#2, 3, 6, 7, 8 | 9-14 |
6 |
#1de, 8, 10a, 11def, 12ab, 14 | 9-21 |
7 |
#1, 4, 6, 7, 9, 10, 14 | 9-21 |
8 |
#1, 4, 5, 7 | 9-21 |
9 |
#1, 2, 3, 5, 7 | 9-21 |
10 |
#1cdghij, 4, 5cdef | 9-30 |
11 |
#1, 3, 5, 7, 12, 16b, 25a, 25c | 9-30 |
11 |
Extra Credit: #18 | 9-30 |
13 |
#1, 3, 6-9, 13ac + Extra Credit (see handout) | 10-7 |
14 |
#1-3, 5, 8, 9 | 10-7 |
15 |
#1-4, 6, 9, 11-13 | 10-7 |
16 |
#1, 2, 3, 7, 8, 27, 28; Extra credit: Sec. 16 #31 | 10-14 |
18 |
#1, 3, 5 | 10-14 |
19 |
#1, 3, 4, 5, 8, 11ab | 10-14 |
20 |
#1, 2, 3, 4 | 11-2 |
21 |
#1, 4b, 8a, 8b, 8c, plus: #17: Prove by induction on n that for all natural numbers n, 2^0 + 2^ 1 + 2^2 + ... + 2^n = 2^(n+1) - 1 |
11-2 |
46 |
#1, 2, 3, 6, 9, 10, 12, 16 | 11-7 |
47 |
#1, 2, 3, 4, 5, 6, 8 Extra credit: Prove or disprove: There exists a graph G = (V, E) with |V| = 5 such that G has no 3-clique and the complement of G has no 3-clique. |
11-7 |
48 |
#1, 6, 8, 9 Extra Credit: #7 |
11-14 |
49 |
#1, 6, 9 Extra Credit: #17 | 11-14 |
51 |
#1, 3, 4, 8, 13ab, 14 | 11-14 |
23 |
Function Homework Handout | 11-30 |
28 |
#1ade (use definition of big-O); 2abcdef (justify each answer); 3, 5, 6 | 12-8 |
30 |
#5, 6b, 7, 9b, 12abc, 16, 17, 18, 20 | 12-8 |
31 |
#1abcdef, 13, 14, 15, 16 | 12-8 |
Tentative Schedule:
Week |
Date |
M |
W |
R |
F |
1 |
5-Sep |
1, 2 |
3 |
4 |
4, 5 |
2 |
12-Sep |
6 |
7 |
8 |
9 |
3 |
19-Sep |
10 |
11 |
review |
exam 1 |
4 |
26-Sep |
11 |
11 |
13 |
14 |
5 |
3-Oct |
14 |
16 |
16 |
18 |
6 |
10-Oct |
18 |
19 |
20 |
20 |
7 |
17-Oct |
break |
21 |
review |
exam 2 |
8 |
24-Oct |
21 |
21 |
46 |
46 |
9 |
31-Oct |
46 |
47 |
47 |
47 |
10 |
7-Nov |
48 |
48 |
49 |
49 |
11 |
14-Nov |
23 |
23 |
review |
exam 3 |
12 |
21-Nov |
24 |
break |
break |
break |
13 |
28-Nov |
25 |
28 |
28 |
30 |
14 |
5-Dec |
31 |
31 |
review |
review |